Compute Difference Quotient

Compute Difference Quotient

Postby nycmath » Sun Aug 16, 2026 8:37 pm

Precalculus
David Cohen
Edition 3
Chapter 3, Srction 3.1

Compute the difference quotient for the function.

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Re: Compute Difference Quotient

Postby Eigenvalue » Sun Aug 16, 2026 10:08 pm

51. [tex]\frac{4x²-4a²}{x-a}[/tex]
=4([tex]\frac{(x+a)(x-a)}{x-a}[/tex])
=4(x+a)=4x+4a

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Re: Compute Difference Quotient

Postby Eigenvalue » Sun Aug 16, 2026 10:15 pm

52. [tex]\frac{-2x²+9-(-2a²+9)}{x-a}[/tex]
=[tex]\frac{-2x²+9+2a²-9}{x-a}[/tex]
=[tex]\frac{-2x²+2a²}{x-a}[/tex]
=-2([tex]\frac{x²-a²}{x-a}[/tex])
=-2(x+a)=-2x-2a

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Re: Compute Difference Quotient

Postby Eigenvalue » Sun Aug 16, 2026 10:32 pm

53. [tex]\frac{x²-2x+4-a²+2a-4}{x-a}[/tex]
=[tex]\frac{x²-a²-2x+2a}{x-a}[/tex]
=[tex]\frac{(x-a)(x+a-2)}{(x-a)}[/tex]
=x+a-2

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Re: Compute Difference Quotient

Postby Eigenvalue » Sun Aug 16, 2026 10:35 pm

[tex]\frac{2x²-x+1-2a²+a-1}{x-a}[/tex]
=[tex]\frac{2x²-2a²-x+a}{x-a}[/tex]
=[tex]\frac{(x-a)(2x+2a-1)}{x-a}[/tex]
=2x+2a-1

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Re: Compute Difference Quotient

Postby Eigenvalue » Sun Aug 16, 2026 10:40 pm

55. [tex]\frac{4x³-4a³}{x-a}[/tex]
=4([tex]\frac{x³-a³}{x-a}[/tex])
=4([tex]\frac{(x-a)(x²+x+1)}{x-a}[/tex]
=4(x²+x+1)=-4x²-4x+4
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Re: Compute Difference Quotient

Postby Eigenvalue » Sun Aug 16, 2026 10:44 pm

56. [tex]\frac{-x³+2+a³-2}{x-a}[/tex]
=-([tex]\frac{x³-a³}{x-a}[/tex])
=-(x²+x+1)
=-x²-x-1

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Re: Compute Difference Quotient

Postby Eigenvalue » Mon Aug 17, 2026 7:16 am

57.[tex]\frac{(5/(x+h)²)-(5/x²)}{h}[/tex]
=[tex]\frac{5x²-5(x+h)²}{h(x²)(x+h)²}[/tex]
=[tex]\frac{-10hx-5h²}{h(x²)(x+h)²}[/tex]
=[tex]\frac{-10x-5h}{x²(x+h)²}[/tex]

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Re: Compute Difference Quotient

Postby Eigenvalue » Mon Aug 17, 2026 7:22 am

[tex]\frac{(-3/(x+h)²)-(-3/x²)}{h}[/tex]

=[tex]\frac{-3x²+3(x+h)²}{h(x²)(x+h)²}[/tex]
=[tex]\frac{6xh+3h²}{h(x²)(x+h)²}[/tex]
=[tex]\frac{6x+3h}{x²(x+h)²}[/tex]

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Re: Compute Difference Quotient

Postby nycmath » Mon Aug 17, 2026 8:38 am

Eigenvalue wrote:51. [tex]\frac{4x²-4a²}{x-a}[/tex]
=4([tex]\frac{(x+a)(x-a)}{x-a}[/tex])
=4(x+a)=4x+4a


The site only allows three thumbs up per every few hours. A job well-done. You are amazingly smart.

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Re: Compute Difference Quotient

Postby nycmath » Mon Aug 17, 2026 8:39 am

Eigenvalue wrote:52. [tex]\frac{-2x²+9-(-2a²+9)}{x-a}[/tex]
=[tex]\frac{-2x²+9+2a²-9}{x-a}[/tex]
=[tex]\frac{-2x²+2a²}{x-a}[/tex]
=-2([tex]\frac{x²-a²}{x-a}[/tex])
=-2(x+a)=-2x-2a


Easy to follow steps. Great work.

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Re: Compute Difference Quotient

Postby nycmath » Mon Aug 17, 2026 8:40 am

Eigenvalue wrote:53. [tex]\frac{x²-2x+4-a²+2a-4}{x-a}[/tex]
=[tex]\frac{x²-a²-2x+2a}{x-a}[/tex]
=[tex]\frac{(x-a)(x+a-2)}{(x-a)}[/tex]
=x+a-2


You outshine them all.

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Re: Compute Difference Quotient

Postby nycmath » Mon Aug 17, 2026 8:40 am

Eigenvalue wrote:[tex]\frac{2x²-x+1-2a²+a-1}{x-a}[/tex]
=[tex]\frac{2x²-2a²-x+a}{x-a}[/tex]
=[tex]\frac{(x-a)(2x+2a-1)}{x-a}[/tex]
=2x+2a-1


Terrific. Wonderful. Great work.

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Re: Compute Difference Quotient

Postby nycmath » Mon Aug 17, 2026 8:41 am

Eigenvalue wrote:55. [tex]\frac{4x³-4a³}{x-a}[/tex]
=4([tex]\frac{x³-a³}{x-a}[/tex])
=4([tex]\frac{(x-a)(x²+x+1)}{x-a}[/tex]
=4(x²+x+1)=-4x²-4x+4


You are cooking with gas.

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Re: Compute Difference Quotient

Postby nycmath » Mon Aug 17, 2026 8:42 am

Eigenvalue wrote:56. [tex]\frac{-x³+2+a³-2}{x-a}[/tex]
=-([tex]\frac{x³-a³}{x-a}[/tex])
=-(x²+x+1)
=-x²-x-1


Simple and direct. Thank you.

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Re: Compute Difference Quotient

Postby nycmath » Mon Aug 17, 2026 8:42 am

Eigenvalue wrote:57.[tex]\frac{(5/(x+h)²)-(5/x²)}{h}[/tex]
=[tex]\frac{5x²-5(x+h)²}{h(x²)(x+h)²}[/tex]
=[tex]\frac{-10hx-5h²}{h(x²)(x+h)²}[/tex]
=[tex]\frac{-10x-5h}{x²(x+h)²}[/tex]


Impressive and direct.

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Re: Compute Difference Quotient

Postby nycmath » Mon Aug 17, 2026 8:43 am

Eigenvalue wrote:[tex]\frac{(-3/(x+h)²)-(-3/x²)}{h}[/tex]

=[tex]\frac{-3x²+3(x+h)²}{h(x²)(x+h)²}[/tex]
=[tex]\frac{6xh+3h²}{h(x²)(x+h)²}[/tex]
=[tex]\frac{6x+3h}{x²(x+h)²}[/tex]


Wonderfully-done. Great math skills for sure.

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