Find Domain of Functions

by **nycmath** » Sat Aug 15, 2026 8:02 pm

Precalculus
Michael Sullivan
Edition 10
Chapter 2, Section 2.1

Find domain of functions.

See attachment.

by **Eigenvalue** » Sat Aug 15, 2026 9:21 pm

[tex]\sqrt{1-x}[/tex]>0
1-x>0
x<1

[4 is a set positive value, so [tex]\sqrt{x-9}[/tex]>0
x-9>0
x>9

by **nycmath** » Sat Aug 15, 2026 11:54 pm

Eigenvalue wrote:[tex]\sqrt{1-x}[/tex]>0
1-x>0
x<1

[4 is a set positive value, so [tex]\sqrt{x-9}[/tex]>0
x-9>0
x>9

I think for 60, we set the radical to be greater than or equal to 0. Yes?

by **Eigenvalue** » Sat Aug 15, 2026 11:56 pm

[yes, I made a mistake. it should be greater than or equal to 0

by **nycmath** » Sat Aug 15, 2026 11:57 pm

Eigenvalue wrote:[yes, I made a mistake. it should be greater than or equal to 0

Correct.