Cost of Trans-Atlantic Travel

Cost of Trans-Atlantic Travel

Postby nycmath » Fri Aug 14, 2026 4:16 am

Precalculus
Michael Sullivan
Edition 10
Chapter 2, Srctiom 2.1

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Re: Cost of Trans-Atlantic Travel

Postby Math Tutor » Fri Aug 14, 2026 3:00 pm

Just substitute the ground speed x into C(x) = 100 + x/10 + 36000/x. The 3000-mile distance is already built into the formula, so you don't need it here.

(a) No wind: x = 500
C(500) = 100 + 50 + 72 = $222.00

(b) Head wind of 50 mph: x = 500 - 50 = 450
C(450) = 100 + 45 + 80 = $225.00

(c) Tail wind of 100 mph: x = 500 + 100 = 600
C(600) = 100 + 60 + 60 = $220.00

(d) Head wind of 100 mph: x = 500 - 100 = 400
C(400) = 100 + 40 + 90 = $230.00

Notice the pattern: a tail wind raises the ground speed and lowers the cost per passenger, while a head wind slows the plane down and raises the cost.

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Re: Cost of Trans-Atlantic Travel

Postby nycmath » Fri Aug 14, 2026 3:24 pm

Math Tutor wrote:Just substitute the ground speed x into C(x) = 100 + x/10 + 36000/x. The 3000-mile distance is already built into the formula, so you don't need it here.

(a) No wind: x = 500
C(500) = 100 + 50 + 72 = $222.00

(b) Head wind of 50 mph: x = 500 - 50 = 450
C(450) = 100 + 45 + 80 = $225.00

(c) Tail wind of 100 mph: x = 500 + 100 = 600
C(600) = 100 + 60 + 60 = $220.00

(d) Head wind of 100 mph: x = 500 - 100 = 400
C(400) = 100 + 40 + 90 = $230.00

Notice the pattern: a tail wind raises the ground speed and lowers the cost per passenger, while a head wind slows the plane down and raises the cost.


I could not figure it out. You are amazing. Thank you.

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