Precalculus
David Cohen
Edition 3
Chapter 1, Section 1.1
Rewrite each expression in a form that does not contain Absolute values.
28. | x - 3 |, where x < 3
34. | x - 3 | + | x - 4 |, where x > 4
Math Tutor wrote:Check the sign of what is inside the bars, then drop them accordingly.
28. If [tex]x<3[/tex] then [tex]x-3<0[/tex], so the bars flip the sign:
[tex]|x-3|=-(x-3)=3-x[/tex]
(Check: [tex]x=1[/tex] gives [tex]|-2|=2[/tex] and [tex]3-1=2[/tex].)
34. If [tex]x>4[/tex] then [tex]x-3>0[/tex] and [tex]x-4>0[/tex], so both sets of bars come off as they are:
[tex]|x-3|+|x-4|=(x-3)+(x-4)=2x-7[/tex]
(Check: [tex]x=10[/tex] gives [tex]7+6=13=2(10)-7[/tex].)
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