Prove that there exists a real second-order square matrix A

Prove that there exists a real second-order square matrix A

Postby Guest » Mon Jun 29, 2020 10:30 pm

Is there a man who can solve this proof problem?

X is a second-order square matrix of any real number.
Prove that there exists a real second-order square matrix A, B, and C such that X=(A^2)+(B^2)+(C^2).
Guest
 

Re: Prove that there exists a real second-order square matri

Postby HallsofIvy » Wed Jul 29, 2020 6:52 pm

Guest wrote:Is there a man who can solve this proof problem?
You don't think a woman could answer?

X is a second-order square matrix of any real number.
Prove that there exists a real second-order square matrix A, B, and C such that X=(A^2)+(B^2)+(C^2).

This isn't very clear. I know what a "second-order square matrix" is but I'm not clear on what ''of any real number" means. Do you mean "of any real numbers"- that it is a real matrix.

Then you say "There exist a real second-order square matrix A, B, and C". Those are three matrices! Did you mean three matrices, A, B, and C?

HallsofIvy
 
Posts: 260
Joined: Sat Mar 02, 2019 9:45 am
Reputation: 96


Return to Algebra - Matrices, Determinants, Subspaces, Vectors, Rings, Complex Numbers



Who is online

Users browsing this forum: No registered users and 1 guest