Need help : Rank of Determinant

Need help : Rank of Determinant

Postby Mahmoud Ibrahim » Sun Jul 01, 2018 4:47 am


Please , I need help for the attached question . Thanks
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matrix.png
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Re: Need help : Rank of Determinant

Postby nathi123 » Sun Jul 01, 2018 3:54 pm

If rank of A is 2 , then the determinant of A must be equal to 0 ( det A = 0 ) Det A = 2.0.(-1) + 4.3.k+1.1.2 - 2.0.3 - 1.(-1).k-2.4.1=12k+2 - 8 +k =13k - 6
[tex]detA=0\Leftrightarrow k = \frac{6}{13}[/tex]

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Re: Need help : Rank of Determinant

Postby Mahmoud Ibrahim » Mon Jul 09, 2018 5:15 am

Thanks very much.

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Re: Need help : Rank of Determinant

Postby Guest » Sun Jul 29, 2018 9:18 pm

Mat_Rank.png
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Please. In this question, det(A)[tex]\ne[/tex] zero
And any minor determinant containing K not equal zero.
How can I find the real value of K ?
Thank you very much.
Guest
 

Re: Need help : Rank of Determinant

Postby Guest » Sun Jul 29, 2018 10:40 pm

Note:
the second row = the first + 1.
As : the first column , 0 = -1 + 1 and in the third column 2 = 1 + 1
Is this means that in the second column K = 3 + 1 , then k = 4 ???
Is this answer correct ? If so , why the question said that R(A) = 3 ?.
In this case what we get from R(A) = 3 ??
Thank you again.
Guest
 


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