How to solve complex

How to solve complex

Postby Guest » Wed Mar 14, 2018 1:27 pm

[tex]Im\frac{\sqrt{2}+i\sqrt{2}}{1-i\sqrt{3}}[/tex]
Guest
 

Re: How to solve complex

Postby nathi123 » Fri Mar 16, 2018 9:36 am

Let the complex number is z = [tex]\frac{\sqrt{2}+i\sqrt{2}}{1-i\sqrt{3}}=\frac{\sqrt{2}(1+i)(1+i\sqrt{3})}{(1-i\sqrt{3})(1+i\sqrt{3})}[/tex]
[tex]\Rightarrow z=\frac{\sqrt{2}(1+i)(1+i\sqrt{3})}{1-3i^{2}}=\frac{\sqrt{2}}{4}(1-\sqrt{3}+(1+\sqrt{3})i)\Rightarrow Imz = \frac{\sqrt{2}(1+\sqrt{3})}{4}[/tex]
(as [tex]i^{2}= -1[/tex]).

nathi123
 
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Re: How to solve complex

Postby Guest » Wed Mar 28, 2018 4:55 pm

I found that online calculator can calculate complex expressions
http://calcpad.net/Calculator
Select 'Complex' and write
im((sqr(2) + i*sqr(2))/(1 - i*sqr(3)))
I get
0.965926
However, if this is for your school, will not learn anything like that.
Try to solve by yourself and then use it only to check your answer.
Guest
 

Re: How to solve complex

Postby Guest » Tue Oct 01, 2019 12:52 pm

Guest wrote:I found that online calculator can calculate complex expressions
http://calcpad.net/Calculator
Select 'Complex' and write
im((sqr(2) + i*sqr(2))/(1 - i*sqr(3)))
I get
0.965926

Do you understand that this is NOT the correct answer but only an approximation to it?

However, if this is for your school, will not learn anything like that.
Try to solve by yourself and then use it only to check your answer.
Guest
 


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