Determine the equation for the line of the function that has

Determine the equation for the line of the function that has

The function: f(x) = $$\frac{6}{x^2+3}$$

Had a hard time solving this. Can you solve it too with steps?
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*tangent line
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Re: Determine the equation for the line of the function that

So you want to find the tangent line to the graph of this function? At what point?

The tangent line to y= f(x), at $$x= x_0$$, is $$y= f'(x_0)(x- x_0)+ f(x_0)$$. Here $$f(x)= \frac{6}{x^2+ 3}= 6(x^2+ 3)^{-1}$$. The derivative is $$f'(x)= -6(x^2+ 3)^{-2}(2x)= -\frac{12x}{(x^2+ 3)^2}$$. The tangent line, at $$x= x_0$$, is $$y= -\frac{12x_0}{(x_0^2+ 3)^2}(x- x_0)+ \frac{6}{x_0^2+ 3}$$.
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