No registration required!
by Guest » Tue Apr 19, 2016 2:33 am
[tex]\int(3x^2 +2x) (x^3 + x^2)^4dx[/tex]
[tex]\int 15 lnx dx[/tex]
-
Guest
-
by Stancho Pavlov » Mon Aug 01, 2016 7:10 pm
[tex]\int15lnxdx=15\int lnxdx[/tex]
[tex]\int lnxdx[/tex] we integrate by parts:
[tex]\int lnxdx = xlnx - \int xdlnx = xlnx - \int x\frac 1 x dx = xlnx - \int dx = xlnx - x = x(lnx - 1)+C[/tex]
-
Stancho Pavlov
-
- Posts: 2
- Joined: Mon Aug 01, 2016 6:58 pm
- Reputation: 1
Return to Calculus - integrals, lim, functions
Who is online
Users browsing this forum: No registered users and 6 guests