Chain rule generalized formulas

Chain rule generalized formulas

Postby Eigenvalue » Sat Oct 03, 2026 3:24 pm

Here is a list of functions that will be included in the generalized formulas:

f(x)=x
f(x)=x²
f(x)=x³
f(x)=[tex]\frac{1}{x}[/tex]
f(x)=[tex]\frac{1}{x²}[/tex]
f(x)=[tex]\sqrt{x}[/tex]
f(x)=[tex]\sqrt[3]{x}[/tex]
f(x)=|x|
f(x)=sin(x)
f(x)=cos(x)
f(x)=tan(x)
f(x)=csc(x)
f(x)=sec(x)
f(x)=cot(x)
f(x)=sinh(x)
f(x)=cosh(x)
f(x)=tanh(x)
f(x)=csch(x)
f(x)=sech(x)
f(x)=coth(x)
f(x)=versin(x)
f(x)=vercos(x)
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Re: Chain rule generalized formulas

Postby Eigenvalue » Sat Oct 03, 2026 3:26 pm

Thought process:

There are 484 possible generalized formulas as there are 22 possible choices for the first function and 22 possible choices for the second function. It is not needed to divide by 2, as the derivative of f(g(x)) differs from that of g(f(x))

Eigenvalue
 
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Re: Chain rule generalized formulas

Postby Eigenvalue » Sat Oct 03, 2026 3:35 pm

1. y=u
u=x
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=x'=1
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*1=1

2. y=u
u=x²
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(x²)'=2[tex]x^{(2-1) }[/tex]=2x
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*2x=2x

3. y=u
u=x³
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(x³)'=3[tex]x^{(3-1) }[/tex]=3x²
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*3x²=3x²

4. y=u
u=[tex]\frac{1}{x}[/tex]=[tex]x^{-1}[/tex]
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=-[tex]x^{-1-1 }[/tex]=-[tex]x^{-2 }[/tex]
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(-[tex]x^{-2 }[/tex])=[tex]\frac{-1}{x²}[/tex]

4. y=u
u=[tex]\frac{1}{x²}[/tex]=[tex]x^{-2 }[/tex]
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=-2[tex]x^{-2-1 }[/tex]=-2[tex]x^{-3 }[/tex]
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(-2[tex]x^{-3 }[/tex])=[tex]\frac{-2}{x³}[/tex]

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Re: Chain rule generalized formulas

Postby Eigenvalue » Sat Oct 03, 2026 3:46 pm

5. y=u
u=sin(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(sin(x))'=cos(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*cos(x)=cos(x)

6. y=u
u=cos(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(cos(x))'=-sin(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(-sin(x))=-sin(x)

7. y=u
u=tan(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(tan(x))'=sec²(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*sec²(x)=sec²(x)

8. y=u
u=csc(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(csc(x))'=-csc(x)cot(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(-csc(x)cot(x))=-csc(x)cot(x)

9. y=u
u=sec(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(sec(x))'=sec(x)tan(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(sec(x)tan(x))=sec(x)tan(x)

10. y=u
u=cot(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(cot(x))'=-csc²(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(-csc²(x))=-csc²(x)

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