by Eigenvalue » Sat Oct 03, 2026 3:46 pm
5. y=u
u=sin(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(sin(x))'=cos(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*cos(x)=cos(x)
6. y=u
u=cos(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(cos(x))'=-sin(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(-sin(x))=-sin(x)
7. y=u
u=tan(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(tan(x))'=sec²(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*sec²(x)=sec²(x)
8. y=u
u=csc(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(csc(x))'=-csc(x)cot(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(-csc(x)cot(x))=-csc(x)cot(x)
9. y=u
u=sec(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(sec(x))'=sec(x)tan(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(sec(x)tan(x))=sec(x)tan(x)
10. y=u
u=cot(x)
a) [tex]\frac{dy}{dx}[/tex]=[tex]\frac{dy}{du}[/tex]*[tex]\frac{du}{dx}[/tex]
b)Find [tex]\frac{dy}{du}[/tex]
c)[tex]\frac{dy}{du}[/tex]=u'=1
d) Find [tex]\frac{du}{dx}[/tex]
[tex]\frac{du}{dx}[/tex]=(cot(x))'=-csc²(x)
e) Find the product of [tex]\frac{dy}{du}[/tex] and [tex]\frac{du}{dx}[/tex]
[tex]\frac{dy}{dx}[/tex]=1*(-csc²(x))=-csc²(x)