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3.6 Question 232

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3.6 Question 232

Postby Eigenvalue » Mon Sep 28, 2026 9:11 pm

Find dy/dx for each function:

y=[tex]\frac{1}{sin²(x)}[/tex]
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Re: 3.6 Question 232

Postby Eigenvalue » Mon Sep 28, 2026 9:13 pm

Rewrite [tex]\frac{1}{sin²(x)}[/tex] as csc²(x)

y'=(csc²(x))'
=2csc(x)*(csc(x))'
=2csc(x)*(-csc(x)cot(x))
=-2csc²(x)cot(x)

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