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3.6 Question 231

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3.6 Question 231

Postby Eigenvalue » Mon Sep 28, 2026 9:09 pm

Find dy/dx for each function:
y=(2x³-x²+6x+1)³
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Re: 3.6 Question 231

Postby Eigenvalue » Mon Sep 28, 2026 9:09 pm

y'=3(2x³-x²+6x+1)²(2x³-x²+6x+1)'
=3(3x²-2x+6)(2x³-x²+6x+1)
=9x²-6x+18(2x³-x²+6x+1)

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