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3.6 Question 229

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3.6 Question 229

Postby Eigenvalue » Mon Sep 28, 2026 9:00 pm

Find dy/dx for each function:
y=[tex](5-2x)^{-2 }[/tex]
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Re: 3.6 Question 229

Postby Eigenvalue » Mon Sep 28, 2026 9:02 pm

y'=-2[tex](5-2x)^{-3}[/tex]*(5-2x)'
=-2[tex](5-2x)^{-3}[/tex]*(-2)
=[tex]\frac{4}{(5-2x)³}[/tex]

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Re: 3.6 Question 229

Postby nycmath » Mon Sep 28, 2026 9:04 pm

Eigenvalue wrote:y'=-2[tex](5-2x)^{-3}[/tex]*(5-2x)'
=-2[tex](5-2x)^{-3}[/tex]*(-2)
=[tex]\frac{4}{(5-2x)³}[/tex]


Smooth

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