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3.6 Question 228

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3.6 Question 228

Postby Eigenvalue » Mon Sep 28, 2026 8:54 pm

Find dy/dx for each function:
y=(3x²+3x-1)⁴
Eigenvalue
 
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Re: 3.6 Question 228

Postby Eigenvalue » Mon Sep 28, 2026 8:57 pm

y'=4(3x²+3x-1)³(3x²+3x-1)'
=4(3x²+3x-1)³(6x+3)
=(24x+12)(3x²+3x-1)

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Re: 3.6 Question 228

Postby nycmath » Mon Sep 28, 2026 9:03 pm

Eigenvalue wrote:y'=4(3x²+3x-1)³(3x²+3x-1)'
=4(3x²+3x-1)³(6x+3)
=(24x+12)(3x²+3x-1)


Not too bad

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