Eigenvalue wrote:Horizontal tangent line[tex]\rightarrow[/tex] the derivative is 0
f'(x)=-3((sin(x))'cos(x)+sin(x)(cos(x))')
=-3(cos²(x)-sin²(x))
=-3cos(2x)
-3cos(2x)=0
cos(2x)=0
x=[tex]\frac{nπ}{2}[/tex], where n is odd
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