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Find f'(x) for each function
f(x)=sin(x)*tan(x)
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3.5 Question 180
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Re: 3.5 Question 180
by Eigenvalue » Thu Sep 24, 2026 7:33 pm
f'(x)=(sin(x))'tan(x)+sin(x)(tan(x))'
=-cos(x)tan(x)+sin(x)(sec²(x))
=-sin(x)+tan(x)sec(x)
=-cos(x)tan(x)+sin(x)(sec²(x))
=-sin(x)+tan(x)sec(x)
- Eigenvalue
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Re: 3.5 Question 180
by nycmath » Sun Sep 27, 2026 3:46 pm
Eigenvalue wrote:f'(x)=(sin(x))'tan(x)+sin(x)(tan(x))'
=-cos(x)tan(x)+sin(x)(sec²(x))
=-sin(x)+tan(x)sec(x)
You can still answer calculus questions in the same old fashioned way. Correct.
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