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Use the definition of the derivative to find f'(x).
f(x)=[tex]\frac{2}{7}[/tex]x+1
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3.2 Question 56
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Re: 3.2 Question 56
by Eigenvalue » Wed Sep 23, 2026 6:55 pm
f'(x)=[tex]\lim_{x \to 0} \frac{f(x+h)-f(x)}{h}[/tex]
=[tex]\frac{2/7(x+h)+1-(2/7x+1)}{h}[/tex]
=[tex]\frac{2/7h}{h}[/tex]
=[tex]\frac{2}{7}[/tex]
=[tex]\frac{2/7(x+h)+1-(2/7x+1)}{h}[/tex]
=[tex]\frac{2/7h}{h}[/tex]
=[tex]\frac{2}{7}[/tex]
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Re: 3.2 Question 56
by nycmath » Wed Sep 23, 2026 9:16 pm
Eigenvalue wrote:f'(x)=[tex]\lim_{x \to 0} \frac{f(x+h)-f(x)}{h}[/tex]
=[tex]\frac{2/7(x+h)+1-(2/7x+1)}{h}[/tex]
=[tex]\frac{2/7h}{h}[/tex]
=[tex]\frac{2}{7}[/tex]
We are going to be in calculus 1 soon enough. Life is like a passing shadow. Be patient. This is our mission.
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