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Use the definition of the derivative to find f'(x).
f(x)=2-3x
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3.2 Question 55
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Re: 3.2 Question 55
by Eigenvalue » Wed Sep 23, 2026 6:53 pm
f'(x)=[tex]\lim_{x \to 0} \frac{f(x+h)-f(x)}{h}[/tex]
=[tex]\frac{2-3(x+h)-(2-3x)}{h}[/tex]
=[tex]\frac{-3h}{h}[/tex]
=-3
=[tex]\frac{2-3(x+h)-(2-3x)}{h}[/tex]
=[tex]\frac{-3h}{h}[/tex]
=-3
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Re: 3.2 Question 55
by nycmath » Wed Sep 23, 2026 9:12 pm
Eigenvalue wrote:f'(x)=[tex]\lim_{x \to 0} \frac{f(x+h)-f(x)}{h}[/tex]
=[tex]\frac{2-3(x+h)-(2-3x)}{h}[/tex]
=[tex]\frac{-3h}{h}[/tex]
=-3
Great but we are not in calculus 1.
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