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by nycmath » Sun Sep 06, 2026 2:45 pm
I know that d/dx of e^x = e^x.
Why does d/dx of e^x = the same function?
Can you show the proof?
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nycmath
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by Eigenvalue » Sun Sep 06, 2026 10:46 pm
Part H ([tex]e^{x }[/tex]):
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- IMG_20260906_214535~2.jpg (511.79 KiB) Viewed 1 time
Last edited by
Eigenvalue on Mon Sep 07, 2026 1:30 am, edited 1 time in total.
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Eigenvalue
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by Eigenvalue » Sun Sep 06, 2026 10:59 pm
Summary:
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- IMG_20260906_215601~2.jpg (578.44 KiB) Viewed 1 time
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Eigenvalue
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by Eigenvalue » Mon Sep 07, 2026 1:31 am
Part J (sin(x)):
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- IMG_20260907_003017~2.jpg (435.01 KiB) Not viewed yet
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Eigenvalue
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by Eigenvalue » Mon Sep 07, 2026 1:32 am
Part K (cos(x)):
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- IMG_20260907_003200~2.jpg (616.07 KiB) Not viewed yet
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Eigenvalue
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by Eigenvalue » Mon Sep 07, 2026 1:34 am
Part A (x):
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Eigenvalue
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by Eigenvalue » Mon Sep 07, 2026 1:35 am
Parts B (x²) and C (x³):
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- IMG_20260907_003512~2.jpg (290.19 KiB) Not viewed yet
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Eigenvalue
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