by Guest » Tue Dec 11, 2012 6:17 am
[tex]AD = -\phi AB+\phi AC[/tex]
[tex]AE = -\phi AB+AC[/tex]
[tex]BE = -(1+\phi) AB+AC[/tex]
where [tex]\phi = \frac{1+\sqrt{5}}{2}[/tex].
(The trick is to notice various vectors are parallel like AC and ED and the ratio of their lengths is [tex]\phi[/tex]).
Hope this helps,
R. Baber.