by parvez » Sat May 30, 2009 8:50 am
Let no.s be x,y,z.
According to first probelm,
x+y+z=136.5...............................(1)eq.
According to second problem,
8x+4y+6z=a+a+a.........................(2)eq.
From eq. (2)
8x=a...........(3)eq.
4y=a............(4)eq.
6z=a............(5)eq.
From eq.(3),(4)and(5)
8x=4y=6z
y=2x and z=4x/3
put the value of y and z in eq. (1)eq.
x+2x+4x/3=136.5
.
.
.
x=31.5
y=63
z=42