Good night!
Calculating the area:
First, the semiperimeter:
[tex]p=\frac{20+25+30}{2}=\frac{75}{2}=37,5[/tex]
Now, using Heron's Formula:
[tex]A=\sqrt{p(p-a)(p-b)(p-c)}=\sqrt{37,5(37,5-20)(37,5-25)(37,5-30)}=\sqrt{37,5\cdot 17,5\cdot 12,5\cdot 7,5}\Rightarrow A\approx 248,04[/tex]
Now, we have the area, we can use it to calculate the radius of external circle.
[tex]A=\frac{abc}{4R}=\frac{20\cdot 25\cdot 30}{4R}\approx 248,04\\\\\\
R\approx\frac{20\cdot 25\cdot 30}{4\cdot 248,04}\\\\\\
R\approx 15,12m[/tex]
So, the minimum lenght of rope is 15,12m, put in the circumcenter of the triangle
Hope to have helped!