Area of a triangle

by **charlie_eppes** » Thu Mar 05, 2009 2:39 am

The length of the sides of a triangle ABC are: a=65cm, b=70, c=75.
CD and BH are altitudes.
Find the area of the triangle ADH.

by **marry** » Thu Jan 27, 2011 8:52 am

Have you ever studied Cosine rule and Sine rule?
If yes the problem is trivial

by **svetoslav80** » Tue Jan 22, 2013 8:52 pm

[tex]p=\frac{a+b+c}{2}[/tex]
[tex]S = \sqrt{p(p-a)(p-b)(p-c)} = \sqrt{105*40*30*35} = 2100[/tex]

by **jackwilson** » Fri Aug 08, 2014 6:01 am

Yes we can solve it by hero's formula.

by **Guest** » Sat Apr 30, 2016 12:27 pm

Given the length of three sides of a triangle we can find the area of any triangle by using heron's formula.
Let A, B and C be the length of three sides of a triangle.
Calculate the semi perimeter of the triangle.
Semi-Perimeter of triangle(S) = (A + B + C)/2
Now, we can calculate the area of triangle using below mentioned formula.
Area of Triangle = √ S(S-A)(S-B)(S-C))
Where, S is the semi-perimeter that we calculated in first step.
Source : http://www.techcrashcourse.com/2015/03/c-program-to-calculate-area-of-any-triangngled-triangle.html
http://www.techcrashcourse.com/2015/03/c-program-to-calculate-area-of-right-angled-triangle.html

by **garfieldmorse** » Tue Jul 19, 2016 6:52 am

Semi Perimeter= (a+b+c)/2=s
=(65+70+75)/2
S=105
Area=[tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]
=2100 cm

by **leesajohnson** » Sat Aug 20, 2016 5:16 am

S= a+b+c)/2
S= (65+70+75)/2
S= 105

Area= √s(s-a)(s-b)(s-c)
Area = √105(105-65)(105-70)(105-75)
Are = 2100 cm

by **Guest** » Sun Aug 21, 2016 3:20 pm

Garfieldmorse and Leesajohnson ......this was not the question you were asked, so it is definitely not the answer...??? ...you have to find area ADH

by **Guest** » Mon Aug 22, 2016 7:59 pm

Area of triangle ADH is 740

by **Guest** » Mon Aug 22, 2016 8:29 pm

After checking figures.......Area triangle ADH should be 756 ....sorry....