Triangle Ratios

[nycmath]

See attachment.

[Eigenvalue]

A. There is no "x" denoted in the figure, so I cannot determine what y as a function of x would be

B. Use the Pythagorean theorem, given that the triangle is a right triangle
y²+3²=z²
y²+9=z²
Solve for z
z=[tex]\sqrt{y²+9}[/tex]
s is the ratio of y to z; s=[tex]\frac{y}{z}[/tex]
Substitute [tex]\sqrt{y²+9}[/tex] for z
s=[tex]\frac{y}{ \sqrt{y²+9} }[/tex]
s=[tex]\frac{y \sqrt{y²+9} }{y²+9}[/tex]

[nycmath]

A. There is no "x" denoted in the figure, so I cannot determine what y as a function of x would be

B. Use the Pythagorean theorem, given that the triangle is a right triangle
y²+3²=z²
y²+9=z²
Solve for z
z=[tex]\sqrt{y²+9}[/tex]
s is the ratio of y to z; s=[tex]\frac{y}{z}[/tex]
Substitute [tex]\sqrt{y²+9}[/tex] for z
s=[tex]\frac{y}{ \sqrt{y²+9} }[/tex]
s=[tex]\frac{y \sqrt{y²+9} }{y²+9}[/tex]

For part A, there is an x-value given. It is the value of 3. So, x = 3. Can we express y as a function of x = 3?