Help i need to know what cos6x equals

Trigonometry equalities, inequalities and expressions - sin, cos, tan, cot

Help i need to know what cos6x equals

Postby gravy3000 » Mon Dec 15, 2008 5:55 pm

what does cos6x equal? I have a bigger question but i am sure i can get it if i know what this equals it is actually sin6x=4cos6x
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Postby Math Tutor » Wed Dec 17, 2008 7:36 am

Could you write the equation, please.

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This is the solution to the maths problem

Postby adeypeter » Wed Dec 24, 2008 2:49 pm

sin6x=4cos6x
Divide both sides by co6x
sin6x/cos6x=4
Do not forget that whenever the sine function divides the cosine function, it would yield the tangent function
Hence we have,
tan6x=4
Therefore
6x=arc tan(4),
6x=75.963
x=75.963/4
x=18.99

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Postby adeypeter » Wed Dec 24, 2008 2:56 pm

I was the one that posted the last solution to you on the sin6x=4cos6x
I am an experienced maths and physics tutor/lecturer. If you want me to effectively tutor you and break down all basic mathematical concepts to you until you become a guru in few weeks. Then, contact me on my email address fast enough
adeypeter@gmail.com

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Help i need to know what cos6x equals

Postby Marinda » Thu Dec 09, 2010 3:14 am

It is common to come across the terms "domain" and "range" when talking about functions. The first set in a functional relationship is called the domain and the second set is called the range. The notation f:X->Y is the symbolism which stands for the function from set X (the domain) to set Y (the range). The letters X and Y are often replaced by other characters, and it is not uncommon to use the letters g, H, and z for functions. As mentioned previously, X and Y are most common in functional notation because of convention in naming the axes in a coordinate plane by using these letters.

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Re: Help i need to know what cos6x equals

Postby Guest » Wed Sep 28, 2011 3:53 am

question: sin6x=4cos6x
solution: sin6x/cos6x=4cos6x/cos6x
tan6x=4
6x=arctan(4)
6x=75.963
x=75.963/4
x=18.99
if you want more explanation about the problem then try onlie math help.
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