23 Trigonometric identities and functions; Question 23.24

[Eigenvalue]

23.24. Verify that ln(csc(x))=-ln(sin(x)) is an identity

[Eigenvalue]

ln([tex]\frac{1}{y}[/tex])=ln([tex]y^{-1 }[/tex])=-ln(y)
Let y=sin(x)
ln([tex]\frac{1}{sin(x)}[/tex])=ln(csc(x))
=ln([tex](sin(x))^{-1 }[/tex])
=-ln(sin(x))