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Trigonometry equalities, inequalities and expressions - sin, cos, tan, cot
by nycmath » Sun Sep 20, 2026 12:38 pm
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nycmath
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by Guest » Sun Sep 20, 2026 2:51 pm
Hi its Bob
[tex]\frac{\sec A+1}{\sin A+\tan A}=\frac{\frac{1+\cos A}{\cos A}}{\frac{\sin A\cos A+\sin A}{\cos A}}=\frac{1+\cos A}{\sin A\left(\cos A+1\right)}=\frac{1}{\sin A}=\csc A[/tex]
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