Polar to Rectangular Form

[nycmath]

See attachment. Enjoy.

[Eigenvalue]

x=r*cos(theta)
y=r*sin(theta)

2sin(theta)-3cos(theta)=r

2([tex]\frac{y}{r}[/tex])-3([tex]\frac{x}{r}[/tex])=r

2y-3x=r²

r*sin(theta +(π/4))=6
r*(sin(theta)cos(π/4)+cos(theta)sin(π/4))=6

r*([tex]\frac{√2}{2}[/tex]sin(theta)+[tex]\frac{√2}{2}[/tex]cos(theta))=6

[tex]\frac{√2}{2}[/tex]x+[tex]\frac{√2}{2}[/tex]y=6

√2x+√2y=12
x+y=6√2