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Trigonometry equalities, inequalities and expressions  sin, cos, tan, cot
by Guest » Tue Nov 05, 2013 10:41 pm
(1sec u)/(tan u)  (tan u)/(1  sec u) = 2 cot u

Guest

by Guest » Thu Nov 07, 2013 12:19 pm
[tex]\frac{1\sec u}{\tan u} \frac{\tan u}{1\sec u}[/tex]
[tex]= \frac{(1\sec u)^2  \tan^2 u}{\tan u(1\sec u)}[/tex]
[tex]= \frac{12\sec u+ \sec^2 u  \tan^2 u}{\tan u(1\sec u)}[/tex]
[tex]= \frac{22\sec u}{\tan u(1\sec u)}[/tex] (because [tex]\sec^2 u  \tan^2 u=1[/tex])
[tex]= \frac{2}{\tan u}[/tex]
[tex]= 2\cot u[/tex]
Hope that helped,
R. Baber.

Guest

by Guest » Fri Nov 08, 2013 5:28 am
Thank you!

Guest

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