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Trigonometry equalities, inequalities and expressions - sin, cos, tan, cot
by babyj » Mon Dec 03, 2007 6:32 pm
Ok now i have a circle. The problem reads: A satellite is in a circular orbit above the equator. How high must the orbit be for 10 percent of the equator to be visible from the satellite? (Consider the earth's equator to be a circle of radius 3989 miles.) If 10 percent of the equator is to be visible, the arc C'C is 36° (10 percent of 360). Also in triangle ABC, angle C is 90°. You know BC and\angle ABC. How many miles above the earth should the satellite be?
Now that is all they give me and i dont know how to get the answer for the problem. But the picture is 2 triangles inside of a circle but they are comming out of the circle a little and its legs are the radians. Can somebody please help me with this problem please?
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babyj
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by Math Tutor » Tue Dec 04, 2007 5:15 am
Why do not you use
sine rule?
Use the formula here:
viewtopic.php?t=99#236
You have a side and two angles of a triangle and have to find the other side.
Write down, please
what is diffucult to you.
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Math Tutor
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