The Solution of Pi to Infinity

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The Infinity Calculation Method of the Constant Pi for the Legacy and Proof on the Truth by the Knowledge Revelation of the Nature on Pi

Step 1

First we will choose an approximation of Pi.
In this case 355/113 will do and any other fraction could do either but we’ll stick with this one for an example.
Then, we multiply by 2 to get us the approximation for Tau.
2*(355/133) =
6.2831858407079646017699115044247787610619469026548672566371681415...

As we see, we have a remainder given because it doesn’t match Pi exactly of course.
2Pi-6.2831858407079646017699115044247787610619469026548672566371681415...=
-5.335283781248446247378657729926676081039046556146872789568... × 10^-7
or just half of it is,
Pi-355/113=-2.667641890624223123689328864963338040519523278073436394784... × 10^-7 = c1

Step 2

Next we will subtract the approx. of Tau from the number 7.
Hence,
7 - 6.2831858407079646017699115044247787610619469026548672566371681415…
=
0.7168141592920353982300884955752212389380530973451327433628318584...

Then we take approx. Tau again and subtract the obtained result.
6.2831858407079646017699115044247787610619469026548672566371681415… -
0.7168141592920353982300884955752212389380530973451327433628318584...
=
5.5663716814159292035398230088495575221238938053097345132743362831... (a)

Step 3

Further, we take again Pi as a perforation and use negative 4 times Pi and also subtract our gained last result.
Thus,
-4Pi + 5.5663716814159292035398230088495575221238938053097345132743362831... (a) =
-6.999998932943243750310750524268454014664783792190688770625442086...
Next, we add the number 7 to it which gives us a new remainder.
-6.999998932943243750310750524268454014664783792190688770625442086 + 7 = 1.067056756249689249475731545985335216207809311229374557914...×10^-6

Step 4

Also of course, we may have found the new remainder by taking negative 4Pi multiplied with the approx. of Pi and add to the product 4Pi and will receive the negative value for the new remainder. Like this,
-4*(355/113) + 4Pi = -1.0670567562496892494757315459853352162078093112293745579139... × 10^-6

Step 5

Now we can put the decimal values into an equation where we plot for x.
We set x for Pi to get the new result.
(1) (-4*(355/113)+4x) = -1.0670567562496892494757315459853352162078093112293745579139... × 10^-6
(2) Here we take the negative of -4Pi and add number 7 to the result (a) with.
-4x+5.5663716814159292035398230088495575221238938053097345132743362831...+7 =
1.067056756249689249475731545985335216207809311229374557914... × 10^-6

We can see, both solutions are quite the same of course and both differ also by being one negative and one positive by the different approach to calculate for the different variant by compiling the plus and minus for each side unevenly. But here is the knack point and the hidden trick to it. If we take them into an equation for to derive a new result just by plotting and using the terms Pi for x, we can still make out a valuable result without violating the mathematical rules.

Hence,
(i)
-4*(355/113)+4x=-4x+5.5663716814159292035398230088495575221238938053097345132743362831...+7
(ii)
8x= 5.5663716814159292035398230088495575221238938053097345132743362831...+7 +4*(355/113)
(iii)
x=25.132743362831858407079646017699115044247787610619469026548672566.../8=
3.1415929203539823008849557522123893805309734513274336283185840707...

Here we check on the remainder for the value of x and indeed come to the same result as in Step 1 as before and it seems to be paradoxical.

3.1415929203539823008849557522123893805309734513274336283185840707…-Pi=
2.667641890624223123689328864963338040519523278073436394784... × 10^-7

But that’s not finished and we continue on for the trick will proceed by plotting another equation for the variable y put set as Pi.

We set y for Pi and configure the minus and pluses.
(i)
(-4*(355/113)-4y)=+4y+5.5663716814159292035398230088495575221238938053097345132743362831...-7
(ii)
8y=(-4*(355/113)-5.5663716814159292035398230088495575221238938053097345132743362831...+7
(iii)
y=-11.13274336283185840707964601769911504424778761061946902654867256.../8=
-1.39159292035398230088495575221238938053097345132743362831858407...

Further next, we can testify the value for y by subtracting the number 1.75 as an example for to see why it could be a paradoxical result once again like the value for x remains the same as c1.

-1.39159292035398230088495575221238938053097345132743362831858407...-1.75=
-3.14159292035398230088495575221238938053097345132743362831858407…
we check again with Pi.
-3.14159292035398230088495575221238938053097345132743362831858407+Pi=
-2.6676418906242231236893288649633380405195232780734363948... × 10^-7

Nothing out of the extraordinary by now because this is just our remainder of c1 in the negative version as usual but if we plus and add to the y value 3*1.75 instead, then it will get us the double symmetrical backshift to track the middle for the Pi lot.

This result obtained is the main factor of the hidden trick to operate for all the digits of Pi (e.g. as in above).
y+3*1.75= 3.8584070796460176991150442477876106194690265486725663716814159293…

Step 6

Finally, we come to the last operation to retrieve Pi ad infinitum. We have the values for x and y now given and put them together into an equation for each occupy the left and right side in the setting.

Hence,
(A) 4-Pi-3.8584070796460176991150442477876106194690265486725663716814159293…= (B) -x-Pi
which cannot be equal but if we just calculate on without the negative and positive conclusion, we still are able to just adapt it to the equation straight away to let it be defined on depending on the Pi only, as the main deduction for our logical supposition because it may as well be valid and works out legitimate according to mathematical laws to imply.

So we add to the left -Pi and to the right +Pi+3.

A)
For the left side we have then and check it for its remainder.
-2.999999733235810937577687631067113503666195948047672192656360521...
-2.999999733235810937577687631067113503666195948047672192656360521...+Pi=0.141592920353982300884955752212389380530973451327433628318584071...
0.141592920353982300884955752212389380530973451327433628318584071...-(Pi-3)=
2.66764189062422312368932886496333804051952327807343639479×10^-7 (c1)
B)
We still check for what the remainder would be for the right side of the equation.
-3.141593187118171363307268121145275876864777503279761435662223549…-Pi=
-6.283185840707964601769911504424778761061946902654867256637168141... and
-6.283185840707964601769911504424778761061946902654867256637168141…+2Pi=
-5.33528378124844624737865772992667608103904655614687278956... × 10^-7
which is the remainder from Tau from the beginning of Step 1.

Hence, A and B will complement in our final result in true balance as through tarrying given.

Proof and evidential indication:
Now thus, for the ending to reveal the Infinity Calculation Method of the Constant Pi, we will take g for to put Pi as our designated variable and multiply both sides with -1 and obtain.

-4+Pi+3.8584070796460176991150442477876106194690265486725663716814159293…-Pi= +x+Pi +P+3
i.e.
-4+g+3.8584070796460176991150442477876106194690265486725663716814159293… -g = +x+g +g+3

Therefore,
I)
-0.141592386825604176040331014346616387863365347422778013631305113=3.14159292035398230088495575221238938053097345132743362831858407073…+3+2g
II)
2g=-0.141592386825604176040331014346616387863365347422778013631305113...-6.1415929203539823008849557522123893805309734513274336283185840707...
III)
g=
-6.283185307179586476925286766559005768394338798750211641949889183/2=
-Pi

Remark:
In Step 5, we just take the opposite of each remainder in opposite of the equation for calculating for x.
For y we just take an equation which also isn‘t the same on both sides by having changed the minus and pluses.
Note that because all numbers, except the Pi as the variables, are normal decimal numbers derived from the ratio 355/113, we may calculate our x and y as we want to in our liked preferences.


Further next on, we can see that both cancel each one another out to solve us for Pi because the x is higher and the y is lower by c1=c2 through having the equation differ in value for configuration. Therefore, we could manage with Step 5 and 6 to fit in for our shifting to even the division by 2 to obtain the constant Pi exactly and perfectly accurate and also absolutely legitimate by still holding the basic mathematical laws.

Conclusion:
We can see here exactly that Pi can be calculated to all its digits by means of decimal numbers taken from the approximation for Pi in my simple calculation for a new method to help the computer just match out the numbers for Pi in this demonstration by balancing the lower and the upper boundary for to break even on the constant Pi and therefore it is the most fastest way to solve Pi. Logically seen, the Infinity Calculation Method of Pi is a truly amazing marvel in the history of mathematics and the hidden secret had to be overcome by the trick released from shifting through matching the solving scheme of constructing the right pattern fit to break even for the middle margin of Pi between its upper and lower boundary of the approximation of Pi from the fraction 355/113.


Q.E.D.