by **Guest** » Mon Apr 27, 2020 9:21 pm

No, in a/(a+ b) the two "a"s do not cancel out. If a= 2 and b= 5, for example, 2/(2+ 5)= 2/7, not 1/5. Also I am going to interpret the "x" in 100xd^h as multiplication, not another variable. Algebraically that would be better written 100d^h.

I would start by replacing d^h by "u" and write it as y= 100u/(u+ k^h).

Multiply on both sides by u+ k^h: y(u+ k^h)= yu+ yk^h= 100u.

Subtract yu from both sides: yk^h= 100u- yu= (100- y)u.

Divide both sides by 100- y: yk^h/(100- y)= u.

Now put d^h back for u: d^h= yk^h/(100- y).

And finally take the kth root of both sides: d= [k^hy/(100-y)]^{1/h}= k[(100- y)]{1/h}.