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Algebra 2
by lukash » Mon Oct 29, 2007 5:00 am
I'm very interested in solving this [tex](1/3)^{2log_{1/3}cos\pi/6}[/tex] ???
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lukash
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by Math Tutor » Mon Oct 29, 2007 5:17 am
[tex]= (1/3)^{log_{1/3} (cos\pi/6)^2} = (cos\pi/6)^2 = \frac{3}{4 }[/tex]
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