lg^2x - lgx - 2 > 0

[lukash]

to solve this:
lg²x - lgx - 2 > 0 . The answer is x[tex]\in[/tex] (0;0,1) [tex]\cup[/tex] (100,[tex]\infty[/tex] )

[lukash]

If you'll be able show me the graphing cause i've got problem with the exercise mainly in entering the numbers.Thank you very much!!!

[Math Tutor]

http://www.math10.com/en/algebra/logari ... ln-lg.html

Go down, please.
There are 3 tools for drawing graphs.