1. Expand
(a). [tex]\sqrt{1+2x}[/tex]
(b). [tex](2x-\frac{1}{x})^{12}[/tex]
2. Use the expansion of [tex](1+\frac{x}{2})^{8}[/tex] to find the value of [tex](0.99)^{8}[/tex]
Please How do i solve these?
Jesse. Nigeria
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