Rate

Algebra

Rate

Postby Guest » Sat Oct 28, 2017 11:24 pm

One train starts 1 and 1/3 hrs. after another train, and overtakes it in 2 hrs. Determine rate of slower train.

Faster train: 50 mph.
Slower train: x

Rate * Time = Distance.

Rate = Distance / Time

Faster - 50 * t - 1.33

Slower - x * t = xt.

Not sure how to proceed.





Guest
 

Re: Rate

Postby Guest » Mon Oct 30, 2017 1:43 pm

The path of the both trains is the same

The first train travel t time the faster one t - 1.33

t*v = (t-1 1/3)*50

Qe know t = 2

2v= (2/3)*50

Guest
 

Re: Rate

Postby Guest » Mon Oct 30, 2017 3:54 pm

Thanks.

Guest
 


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