Linear Algebra Conditions


Linear Algebra Conditions

Postby Guest » Wed Feb 15, 2017 8:03 am
The answers is b) ab≠1, but I have no clue how to get to that answer... Can someone help me? :D

Re: Linear Algebra Conditions

Postby Guest » Thu Feb 23, 2017 10:35 am

Well as solved it this can easily be done with determinants. If a square matrix's determinant does not equal zero, then that square matrix will have an inverse hence having a unique solution. Since this is a 2x2 matrix, just compute the determinant with the condition that it cannot equal zero:
(1)(2)-(2ab) =/= 0
2 =/= 2ab
1=/= ab

Re: Linear Algebra Conditions

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Re: Linear Algebra Conditions

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