Dimensions

[Guest]

The length of a rectangle is 12 in. more than the side of a square and the width is 4 in. less. The area of the rectangle is 16 sq. in. more than the square. Determine dimensions of each.

My attempt:

Area = length * width

Let s = side of square

Square:

Length: s Width: s Area: s^2

Rectangle:

Length: ( s + 12 ) Width: ( s - 4 ) Area: (s + 12) (s - 4)

(s + 12) ( s - 4) = s^2 + 16

s^2 - 4s + 12s - 48 = s^2 + 16

s^2 - s^2 + 8s - 48 + 48 = 64

8s = 64

s = 8

Rectangle:

Length: 20 in. Width: 4 in. Area: 80 sq. in.

Square:

64 sq. in.

80 - 64 = 16

Where am I correct ?

[Guest]

No mistakes. You nailed it.

R. Baber.

[Guest]

Thanks.

[leesajohnson]

Your solution is correct.

[Guest]

Thanks.