Revolutions Per Minute

Algebra 2

Revolutions Per Minute

Postby Guest » Sat Nov 14, 2015 2:29 am

The driving wheels of a train engine are 16 ft. in circumference. When the engine obtains 60 miles per hour, determine the number of revolutions per minute the wheels make.

My partial attempt:

The wheels travel 16 ft. in one revolution.

60 miles x 5280 = 84480 ft.

60 mph x 88 feet per minute = 5280 ft. = 1 mi. per min.

Unsure how to proceed from here.
Guest
 

Re: Revolutions Per Minute

Postby Guest » Sat Nov 14, 2015 5:50 pm

You have figured out that 60 mph is 1 mile per minute, and that is 5280 feet per minute.
Every 16 feet will be 1 revolution of the wheel so how many "16 feet" is there in 5280 feet..???!
That will give you the revolutions per minute
Guest
 

Re: Revolutions Per Minute

Postby Guest » Sat Nov 14, 2015 8:08 pm

5280 / 16 = 330 revolutions per minute.

??
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