Number - Revolutions

Algebra 2

Number - Revolutions

Postby Guest » Wed Nov 11, 2015 1:50 am

Determine number of revolutions a wheel 5 ft. in diameter makes in traveling 24 miles.

My attempt:

pi x diameter = circumference


3.1416 x 5 = 15.708 ft.

24 x 5280 = 126720 ft.

126720 / 15.708 = 8067.22 = 8067

Where did I make the error(s)?
Guest
 

Re: Number - Revolutions

Postby Guest » Wed Nov 11, 2015 3:11 pm

Where did YOU make the error(s)?
What error(s) did YOU make?
Guest
 

Re: Number - Revolutions

Postby Guest » Wed Nov 11, 2015 3:44 pm

The statement says - A wheel, 5 ft. in diameter, in traveling 24 miles, makes 10,000 revolutions.

I thought I had miscalculated / omitted something.
Guest
 

Re: Number - Revolutions

Postby Guest » Wed Nov 11, 2015 5:43 pm

A question:

If my answer is correct, how is the 10,000 obtained ?
Guest
 

Re: Number - Revolutions

Postby Guest » Wed Nov 11, 2015 7:02 pm

Your orig calculation is correct for 5 ft dia wheel rolling 24 miles, each mile having 5280 feet

3.1416 x 5 = 15.708 ft.

10000 revolutions of the wheel would be 157080 feet travelled
Guest
 

Re: Number - Revolutions

Postby Guest » Wed Nov 11, 2015 7:52 pm

Thanks.

So, I guess the statement had an inaccurate answer.
Guest
 

Re: Number - Revolutions

Postby Guest » Thu Nov 12, 2015 8:24 am

5 x 3.1416 = 15.708 feet.

24 x 5280 = 126720 feet in 24 statute miles.
Revolutions = 126720 / 15.708 = 8067 revolutions

24 x 6087 = 146088 feet in 24 nautical miles

Revs = 146088 / 15.708 = 9300 revolutions.........nearer to 10000 revs approx.
Guest
 

Re: Number - Revolutions

Postby Guest » Thu Nov 12, 2015 10:51 am

Thanks.
Guest
 


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