by Guest » Wed Aug 05, 2015 2:24 pm
HS^2 = 18 ......(1).....rearranges gives....H = 18/S^"
S^2 + 4SH = 33 .....(2)
Subs in (2) gives.... S^2 + 4xSx18/S^2 = 33
The S cancel gives...S^2 + 4x18/S = 33
multiply across by S gives S^3 + 72 = 33S
put in standard form gives S^3 - 33S + 72 = 0
This is a cubic equation, if we can a simple rational root this would be a possible answer....
The factors of the first term id S^3 is 1 and the factors of the last term is any number that divides into 72
eg. 1,2,3,4,etc up to 73
Try these in our cubic above and see if we get Zero......
WE see 3 works...so S = 3 is a possible answer
OR we can say (S - 3) is a factor of the cubic equation.
To find any others we can divide (S-3) into the cubic eqn to get a quatratic and that will give 2 more roots
But so far S = 3 therefore H = 2 from the eqns above
which answers this question of the dimensions of the box