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5 Linear and nonlinear equations; Question 5.34
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5 Linear and nonlinear equations; Question 5.34
by Eigenvalue » Sun Oct 11, 2026 3:30 pm
5.34. A rectangle has perimeter 44 cm. Find its dimensions if its length is 5 cm less than twice its width
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Re: 5 Linear and nonlinear equations; Question 5.34
by Eigenvalue » Sun Oct 11, 2026 3:30 pm
Let L be the length and W be the width
2L+2W=44
L=2W-5
See attachment
Area:117
2L+2W=44
L=2W-5
See attachment
Area:117
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