Depth - Water in Cylinder

Algebra

Depth - Water in Cylinder

Postby Guest » Sun Mar 15, 2015 6:55 pm

A drop of water is assumed to be spherical and .1 in. in diameter. Determine depth 1000 drops will fill a hollow cylinder whose base has a radius of .5 in.

Volume of sphere - 4/3 x pi x r^3

Volume of hollow cylinder - pi (R^2 - r^2) h

Volume of water - 1.333 x 3.1416 x 0.05 x 0.05 x 0.05 = 0.00052 x 1000 drops = 0.520 cu. in.

Volume of cylinder - 3.1416 (.5 x .5)

How do I proceed from this point ?
Guest
 

Re: Depth - Water in Cylinder

Postby Guest » Tue Mar 17, 2015 3:35 pm

Volume of 1000 drops = 4/3 x pi x 0.05^3 x 1000 = 0.524 cu. ins

Area of base of cylinder = pi x 0.5^2 = 0.786

Depth of water = 0.524 / 0.786 = 0.667 inches
Guest
 

Re: Depth - Water in Cylinder

Postby Guest » Tue Mar 17, 2015 4:49 pm

A question:

Is the hollow cylinder formula not used due to the only radius given is the base ?
Guest
 

Re: Depth - Water in Cylinder

Postby Guest » Tue Mar 17, 2015 8:12 pm

The hollow cylinder is a container.
As is a hollow pipe with end closed
Like a test tube with flat closed end.
A Cylinder has same radius throughout its length...it is not tapered like a cone
its inside volume is the area of the base multiplied by length or height

The hollow cylinder formula is for finding the volume of the shell or walls, the material the pipe or tube is made from.

In this problem we want the inside volume space, ist capacity, not the volume of the material it is made from.
Guest
 

Re: Depth - Water in Cylinder

Postby Guest » Tue Mar 17, 2015 9:39 pm

Thanks for the information .....
Guest
 

Re: Depth - Water in Cylinder

Postby Guest » Wed May 02, 2018 2:22 pm

"And ur fucking dumb shit"

Don't appreciate the comments. What if you were trying to learn something and someone called you that? Thought this was a HELP forum, not name calling.
Guest
 


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