by Guest » Wed Mar 04, 2015 3:33 pm
We will carry out some stepwise refinement.....
Formula - .2598 * s^2 - I don't know what the .2598 is..
2598 * 6 * 6 * .75 = 7.0146 (area of end)
You looked at a hexagon and you see 6 sides.....
It also looks roughly circular....round circle with bits of the curve cut off to leave 6 straight edges
If it is circular then it has a centre.....
Two adjacent edges join to a point......there are 6 points
If you join opposite points or corners you find they all cross at the centre.
Tha space between the lines look like triangles.....there are 6 of them....around the circle.
They are all the same size.....so they have all the same angles
The angles at the centre will be 360 divided by 6 = 60 degrees
All the lines from the centre out to the edge will be the same length.
So all the triangles will have at least 2 sides the same length with the angle between them = 60 degrees.
A triangle that ha 2 sides equal is an isosoles triangle and also has 2 angles equal
So the 2 equal angles are 180 - 60 = 120 divided by 2 = 60.
So that means all the angles are equal to 60 degrees.
A triangle with all 3 angles equal is an equilateral triangle and also has all side equal.
So the sides of the hexagon must be the same length as the distance from the centre to the outer edge points.
So we have 6 equal triangles, If we can find the area of 1 we can multiply by 6.
A general formula for the area of any triangle is 0.5 x A x B x Sin(angle between them) where A and B is the length of the 2 adjacent sides. and multiply by 6 to get all of them.
So in terms of the hexagon of side length "s" in your question.......A and B are both equal to "s"
Area of hexagon = 6 x 0.5 x (s^2) x Sin60degrees.
Sin 60 = 0.866
0.5 x 6 = 3
3 x 0.866 = 2.598
So Area of hexagon A = 2.598 * S^2
Whis is your starting formula which you seem to have written down many times incorrectly
......Work through the question logically.............