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Find ab
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Re: Find ab
by Eigenvalue » Tue Sep 22, 2026 5:12 pm
3a=48
a=16
[tex]\frac{a}{b}[/tex]=6
a=6b
b=[tex]\frac{a}{6}[/tex]
Substitute [tex]\frac{a}{6}[/tex] for b
ab=([tex]\frac{a}{6}[/tex])(a)
=[tex]\frac{a²}{6}[/tex]
Substitute 16 for a
[tex]\frac{a²}{6}[/tex]=[tex]\frac{16²}{6}[/tex]=[tex]\frac{128}{3}[/tex]
a=16
[tex]\frac{a}{b}[/tex]=6
a=6b
b=[tex]\frac{a}{6}[/tex]
Substitute [tex]\frac{a}{6}[/tex] for b
ab=([tex]\frac{a}{6}[/tex])(a)
=[tex]\frac{a²}{6}[/tex]
Substitute 16 for a
[tex]\frac{a²}{6}[/tex]=[tex]\frac{16²}{6}[/tex]=[tex]\frac{128}{3}[/tex]
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