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Find Domain of Functions
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Re: Find Domain of Functions
by Guest » Sun Sep 06, 2026 2:10 am
$f(x)=\sqrt{\dfrac{1}{x^{2}-4x-5}}$
Need $\dfrac{1}{x^{2}-4x-5}>0 \iff x^{2}-4x-5>0 \iff (x-5)(x+1)>0$.
Domain: $(-\infty,-1)\cup(5,\infty)$
Need $\dfrac{1}{x^{2}-4x-5}>0 \iff x^{2}-4x-5>0 \iff (x-5)(x+1)>0$.
Domain: $(-\infty,-1)\cup(5,\infty)$
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