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Find a
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Re: Find a
by Eigenvalue » Fri Aug 21, 2026 8:53 pm
(a-1)⁴=16
(a-1)⁴-16=0
((a-1)²+4)((a-1)²-4)=0
(a-1)²+4=0
a²-2a+1+4=0
a²-2a+5=0
a=[tex]\frac{2 \pm \sqrt{4-20} }{2}[/tex]=[tex]\frac{2 \pm 4i}{2}[/tex]=1[tex]\pm[/tex]2i
(a-1)²-4=0
a²-2a+1-4=0
a²-2a-3=0
(a-3)(a+1)=0
a=3 or a=-1
(a-1)⁴-16=0
((a-1)²+4)((a-1)²-4)=0
(a-1)²+4=0
a²-2a+1+4=0
a²-2a+5=0
a=[tex]\frac{2 \pm \sqrt{4-20} }{2}[/tex]=[tex]\frac{2 \pm 4i}{2}[/tex]=1[tex]\pm[/tex]2i
(a-1)²-4=0
a²-2a+1-4=0
a²-2a-3=0
(a-3)(a+1)=0
a=3 or a=-1
- Eigenvalue
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Re: Find a
by nycmath » Fri Aug 21, 2026 10:27 pm
Eigenvalue wrote:(a-1)⁴=16
(a-1)⁴-16=0
((a-1)²+4)((a-1)²-4)=0
(a-1)²+4=0
a²-2a+1+4=0
a²-2a+5=0
a=[tex]\frac{2 \pm \sqrt{4-20} }{2}[/tex]=[tex]\frac{2 \pm 4i}{2}[/tex]=1[tex]\pm[/tex]2i
(a-1)²-4=0
a²-2a+1-4=0
a²-2a-3=0
(a-3)(a+1)=0
a=3 or a=-1
I like your vertical form reply. It's easy to follow the steps.
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