There are two people trying to help you now. To distinguish myself I end my posts with "R. Baber". So it was not my suggestion to "Forget the above posts and do it again" but someone else's. I will let them explain the step "B = 7/6 T - 24 1/2" from their post.
When I wrote:
(2x/3+10)/7 - 2 = nickel
expand the bracket to get
2x/21 + 10/7 - 2 = nickel
I was simply using the fact that (a + b)/c = a/c + b/c. When you remove the brackets you apply the division to every term inside the bracket. For example (10+4)/2 is 7 (the terms inside the bracket add up to 14, and when we divide by 2 we get 7) but we can remove the bracket using the rule I just outlined to get
(10+4)/2 = 10/2 + 4/2
which of course simplifies to 5+2 which again is 7.
Applying this rule to (2x/3+10)/7 we get (2x/3)/7 +10/7. The term (2x/3)/7 can be simplified further to 2x/21, using the rule for divisions by fractions. The rule is
[tex]\frac{a}{b}\div\frac{c}{d} = \frac{a}{b}\times\frac{d}{c} = \frac{a\times d}{b\times c}[/tex]
We can apply this to (2x/3)/7 (using the fact that 7 is the same as 7/1)
[tex]\frac{2x}{3}\div\frac{7}{1} = \frac{2x}{3}\times\frac{1}{7} = \frac{2x\times 1}{3\times 7} = \frac{2x}{21}.[/tex]
Hope this helped,
R. Baber.