Area- Garden

Algebra 2

Area- Garden

Postby Guest » Wed Oct 01, 2014 2:47 pm

A rectangular garden is divided into four parts.

Two parts have the same area.

Third part- twice as large as each of the first two parts.

Last part- Area is twenty feet larger than each of the first two parts.

Garden dimensions- 17 feet by 10 feet.

Calculate area of each part.

area = length * width

Let w, x, y, z = the four parts.

17 * 10 = 170 ft.^2 = area of garden.

w = x
y = 2w
y = 2x

z = w + 20
z = x + 20

w + x + y + z = 170

I am not sure how to proceed.
Guest
 

Re: Area- Garden

Postby Guest » Wed Oct 01, 2014 7:49 pm

Did you read the question..? ? ? ?......

How did you get 4 unknowns ? ? ?

All areas seem to be related to the first 2 parts....so the unknown is the first part and everything else is related.

I assume you mean the "Last part" Area is twenty sq feet larger......

Let W equal the area of the first part

Then the 2nd part is also W

The 3rd part is 2W

The Last 4th part is W + 20

We know from the question they all add up to 170

W + W + 2W + W + 20 = 170

5W + 20 = 170

5W = 150

W = 30

So first part is..... 30 sq.feet
So second part is ... 30 sq.feet
So third part is .... 60 sq.feet
So fourth part is ... 50 sq.feet
Guest
 

Re: Area- Garden

Postby Guest » Wed Oct 01, 2014 9:31 pm

Two parts have the same area.

Third part- twice as large as each of the first two parts.

Last part- Area is twenty feet larger than each of the first two parts.

"How did you get 4 unknowns ? ? ?"

I guess I was trying to calculate as if the parts were combined.

"I assume you mean the "Last part" Area is twenty sq feet larger......"

I was- omission- sorry.
Guest
 


Return to Algebra 2



Who is online

Users browsing this forum: No registered users and 2 guests