by Guest » Sun Aug 31, 2014 6:59 am
We are using algebra to provide a solution.
and we are using simultaneous equations in particular.
In the question we are told 2 things about selling fruit on week1 and week2.
1......how many pieces were sold in week1.....108
2......how many times more of each fruit was sold in week2 also the total of fruit sold in week2......5 times apples and 3 times oranges and total of 452 fruit...apples+oranges.
So if we.... Let x=apples and y=oranges sold in week1
x + y = 108 .....this is what we are told for week1 ....eqn1
5x + 3y = 452 .....this is what we are told for week2 ....eqn2
These are 2 simultaneous equations and we have to find a value for x and y that satisfies both.
In any equation what is added or subtracted from/to one side must be done on the other to keep the equation balanced.
also if I multiply/divide one side by 3 I must do same to other side.
I notice I have a 3y in eqn2 ... So if I multiply eqn1 by 3 I will get..
3x + 3y = 324
and as 3x + 3y equals 324 I can subtract 3x + 3y from the LHS and 324 from the RHS of eqn2 and things are still balanced.
This is called solution by elimination ....multiply/divide to get some term equal then subtract to eliminate....
This gives me .....
2x = 128
so dividing by 2 gives ...
x = 64 apples in week1
and x + y = 108 so y = 108 - 64 = 44
so
y = 44 oranges in week1